Borromean Tribars

borromean tribars

Only the brilliantly inventive Lee Sallows would think of this. The figure above combines Penrose triangles with Borromean rings: Each of the triangles is an impossible object, and they’re united in a perplexing way — although the three are linked together, no two are linked.

(Thanks, Lee.)

Pièce de Résistance

Take an ordinary magic square and replace its numbers with resistors of the same ohmic value. Now the set of resistors in each row, column, and diagonal will yield the same total resistance value when joined together end to end.

This paramagic square, by Lee Sallows, is similar — except that the resistors must be joined in parallel:

sallows paramagic square

Counter Play

A devilish puzzle by Lee Sallows:

lee sallows counter play

In the diagram above, nine numbered counters occupy the cells of a 3×3 checkerboard so as to form a magic square. Any 3 counters lying in a straight line add up to 15. There are 8 of these collinear triads.

Reposition the counters (again, one to each cell) to yield 8 new collinear triads, but now showing a common sum of 16 rather than 15.

Bills of Lading

Devised by Lee Sallows, each of these lists inventories its own contents:

  • fifteen e’s, seven f’s, four g’s, six h’s, eight i’s, four n’s, five o’s, six r’s, eighteen s’s, eight t’s, four u’s, three v’s, two w’s, three x’s
  • sixteen e’s, five f’s, three g’s, six h’s, nine i’s, five n’s, four o’s, six r’s, eighteen s’s, eight t’s, three u’s, three v’s, two w’s, four x’s