In a carnival game, you roll seven ordinary dice and then arrange them to form a 7-digit number.
- If your number is a multiple of 2, you’ll win £2.
- If your number is a multiple of 3, you’ll win £3.
- If your number is a multiple of 4, you’ll win £4.
- If your number is a multiple of 5, you’ll win £5.
- If your number is a multiple of 6, you’ll win £6.
- If your number is a multiple of 7, you’ll win £7.
The catch is that you have to announce the prize you’re attempting before you roll the dice. Which prize should you pick?
At first it seems that the £2 prize must be best. If even one of the seven dice produces an even number, you can put that at the end of string and fulfill the condition. This will happen 99.2 percent of the time.
Surprisingly, though, choosing 7 has an even higher success rate, 99.997 percent! “In fact, almost all numbers can be rearranged to make a multiple of 7,” writes James Grime. “But finding the multiple of 7 is the tricky part.” See the paper below for a strategy that will win the jackpot nearly every time.
(James Grime, “The Seven Dice Shuffle,” Recreational Mathematics Magazine 13:22 [June 2026], 95-101.)


